The owner of a bicycle shop reported his inventory of bicycles and tricycles in an unusual way. He said he co?
The owner of a bicycle shop reported his inventory of bicycles and tricycles in an unusual way. He said he counted 126 wheels and 108 pedals. How many bikes and trikes does he have?
If we use b as the number of bikes and t and the number by trikes then using his count we can create the system of equations
2b + 3t = 126 <– each bike has 2 wheels, and each trike 3
2b + 2t = 108 <– both have 2 pedals each.
Solve that system and you’ll get the number of bikes and trikes, the elimination method works fantastically here.
Let b = number of bicycles and t = number of tricycles.
2b + 3t = 126
2b + 2t = 108
solve the system of equations:
2b = 126 - 3t
2b = 108 - 2t
126 - 3t = 108 - 2t
18 = t
2b + 2(18) = 108
2b = 108 - 36 = 72
b = 36
References :
Comment by IggyRocko — February 22, 2010 @ 5:55 pm
If we use b as the number of bikes and t and the number by trikes then using his count we can create the system of equations
2b + 3t = 126 <– each bike has 2 wheels, and each trike 3
2b + 2t = 108 <– both have 2 pedals each.
Solve that system and you’ll get the number of bikes and trikes, the elimination method works fantastically here.
References :
Comment by ?o? — February 22, 2010 @ 6:27 pm
Each bike and trike has 2 pedals.
Let b = no of bikes
and t = no of trikes
2b + 2t = 108
A bike has two wheels and a trike has 3.
2b + 3t = 126
Subtracting, t = 18
2b + 2(18) = 108
2b + 36 = 108
2b = 72
b = 36
There are 36 bikes and 18 trikes.
References :
Comment by Ed I — February 22, 2010 @ 6:51 pm
Let 2 be the # of wheels on each bike and 108 be the # of pairs of pedals on the back shelf of the store.
So, 63 bikes and 108 pairs of pedals in the back.
References :
Comment by Rik — February 22, 2010 @ 7:03 pm